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Mathematics 7 Online
OpenStudy (aripotta):

Solve this by factoring?? y = -0.35x^2 + 0.994x + 2.77426

OpenStudy (aripotta):

can you explain why i can't use factoring

OpenStudy (aripotta):

please :]

OpenStudy (anonymous):

that's a quadratic formula problem.

OpenStudy (aripotta):

but why couldn't i factor

OpenStudy (anonymous):

you can factor.

OpenStudy (aripotta):

.-.

OpenStudy (aripotta):

what do you mean

OpenStudy (aripotta):

i'm laughing too

OpenStudy (nincompoop):

i am using my ipad and the display is messed up

OpenStudy (aripotta):

i'm so confused *tear rolls slowly down cheek*

OpenStudy (anonymous):

x=−1.7332296368734617 x=4.573229636873461

OpenStudy (aripotta):

i know what the answers are, i just need to know if it can be solved by factoring, and if not, why

OpenStudy (anonymous):

technically it can, but i wouldn't suggest in trying to do it.

OpenStudy (aripotta):

can you show me how

OpenStudy (aripotta):

@rosho don leave me

OpenStudy (anonymous):

doing two problems at the same time. anyways, do you the quadratic formula?

OpenStudy (aripotta):

yea but i gotta factor it...nvm...could i solve it by "completing the square"?

OpenStudy (anonymous):

you can solve it by using many methods, but what does your teacher mean by factoring it?

OpenStudy (aripotta):

i guess by finding the two numbers whose product is b and sum is c??

OpenStudy (aripotta):

like that kinda factoring??

OpenStudy (anonymous):

i don't think that would be possible without the quadratic formula.

OpenStudy (aripotta):

"show the solutions, or x-intercepts, of the parabola found algebraically by factoring, using the quadratic formula and completing the square. If one of these methods cannot be used, a complete sentence explaining why."

OpenStudy (nincompoop):

completing the squre may be used

OpenStudy (nincompoop):

if you can turn them int a whole number then you have a shot, but you're giving yourself more work

OpenStudy (anonymous):

oh, i just did the quadratic formula.

OpenStudy (aripotta):

idk what i should put down T-T WHAT DO THEY WANT FROM ME (╯°□°)╯︵ ┻━┻

OpenStudy (nincompoop):

just say it is difficult to factor a non-whole number coefficient in the first term

OpenStudy (nincompoop):

can you turn that equation into standard quadratic function?

OpenStudy (aripotta):

wat

OpenStudy (nincompoop):

I wouldn't even bother LAUGHING OUT LOUD

OpenStudy (anonymous):

just enter in the values of a, b, and c into that calculator or graph the function, and solve for x and the complete square is the vertex, and then plug the values of A,Y into this formula A+(Y+X)^2

OpenStudy (anonymous):

\[y=-0.35(x^2-2.84x-7.926)\\ y=-0.35(x-a)(x-b)\]

OpenStudy (anonymous):

one thing for sure only the bigger one is negative say |a|>|b| then "a" is negative and "b" is positive

OpenStudy (anonymous):

sorry, I should have put y=-0.35(x+a)(x+b)

OpenStudy (nincompoop):

ya.... f(x) = a(x-h)^2 + k, a not equal to zero

OpenStudy (nincompoop):

the f(x) is your y = ...

OpenStudy (anonymous):

also \(|a|>2.84>|b|\)

OpenStudy (anonymous):

so, you may scan for some values to the left and right..

OpenStudy (anonymous):

since \[y'=-0.35(2x-2.84)\] and "y" has a minimum at "x=1.42"

OpenStudy (nincompoop):

I am missing something ....

OpenStudy (nincompoop):

you didn't show how you got -7.926

OpenStudy (anonymous):

I factoerd out the -0.37

OpenStudy (anonymous):

also @aripotta you do not have to use any numerical methods, right?

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