Solve this by factoring?? y = -0.35x^2 + 0.994x + 2.77426
can you explain why i can't use factoring
please :]
that's a quadratic formula problem.
but why couldn't i factor
you can factor.
.-.
what do you mean
i'm laughing too
i am using my ipad and the display is messed up
i'm so confused *tear rolls slowly down cheek*
x=−1.7332296368734617 x=4.573229636873461
i know what the answers are, i just need to know if it can be solved by factoring, and if not, why
technically it can, but i wouldn't suggest in trying to do it.
can you show me how
@rosho don leave me
doing two problems at the same time. anyways, do you the quadratic formula?
yea but i gotta factor it...nvm...could i solve it by "completing the square"?
you can solve it by using many methods, but what does your teacher mean by factoring it?
i guess by finding the two numbers whose product is b and sum is c??
like that kinda factoring??
i don't think that would be possible without the quadratic formula.
"show the solutions, or x-intercepts, of the parabola found algebraically by factoring, using the quadratic formula and completing the square. If one of these methods cannot be used, a complete sentence explaining why."
completing the squre may be used
if you can turn them int a whole number then you have a shot, but you're giving yourself more work
oh, i just did the quadratic formula.
idk what i should put down T-T WHAT DO THEY WANT FROM ME (╯°□°)╯︵ ┻━┻
just say it is difficult to factor a non-whole number coefficient in the first term
can you turn that equation into standard quadratic function?
wat
I wouldn't even bother LAUGHING OUT LOUD
just enter in the values of a, b, and c into that calculator or graph the function, and solve for x and the complete square is the vertex, and then plug the values of A,Y into this formula A+(Y+X)^2
\[y=-0.35(x^2-2.84x-7.926)\\ y=-0.35(x-a)(x-b)\]
one thing for sure only the bigger one is negative say |a|>|b| then "a" is negative and "b" is positive
sorry, I should have put y=-0.35(x+a)(x+b)
ya.... f(x) = a(x-h)^2 + k, a not equal to zero
the f(x) is your y = ...
also \(|a|>2.84>|b|\)
so, you may scan for some values to the left and right..
since \[y'=-0.35(2x-2.84)\] and "y" has a minimum at "x=1.42"
I am missing something ....
you didn't show how you got -7.926
I factoerd out the -0.37
also @aripotta you do not have to use any numerical methods, right?
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