heelp for the surface with parametric equations r(s,t)=
heelp for the surface with parametric equations r(s,t)=<st, s+t, s-t>, find the equation of the tangent plane at (2,3,1) Also Find the surface area under the restriction s^2+t^2<=1.
do you know how to find the normal vector of a parametric surface?
Do you know how to find a plane given a normal vector and a point?
no i only know if its in x y z
Give me a second... brb
Okay, the normal vector to the parametric surface \(\mathbf{r}(s,t)\) Is given by \[\large \mathbf{r}_s\times \mathbf{r}_t \]That is, the cross product each of its partial derivatives.
@dan815 Think you can do that part at least?
You will get the normal vector as a function of \(s,t\)
Since the normal vector is changing
-2, t+s, t-s
wut do i do after i get the nomal vector
Find \(s,t\) such that \(\mathbf{r}(s,t)=(2,3,1) \)
Then plug in that \(s,t\) to find the normal vector to the point \((2,3,1) \)
ohh ok thanks i get it now
-2x+3y-z=4
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