find an equation of the tangent to the curve at the given point. f(x)= 2sinx+3 at x=pi/6
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
A tangent is a straight line. Therefore, the equation of a tangent can be written in the form y= mx +c
where m=slope of the tangent
c= y-intercept of the tangent
OpenStudy (anonymous):
to find the slope of the tangent at the point x=pi/6..
\[\frac{ dy }{ dx } (x=\frac{ \pi }{ 6 })\]
OpenStudy (anonymous):
do you get up to that point??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
I plugged pi/6 on for all x
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes....that is correct!
OpenStudy (anonymous):
then what do i do
OpenStudy (anonymous):
f(pi/6)=4
OpenStudy (anonymous):
that step is correct. you found the corresponding y-coordinate of the given x-coordinate (pi/6)
OpenStudy (anonymous):
y-4=m(x-pi/6) ??
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so now we can plug them in the equation y= mx +c to find the value of c.
y=4
x=pi/6
m=sqrt of 3
OpenStudy (anonymous):
is that what you got for your value of the slope (m)??
OpenStudy (anonymous):
how do you get m=sqrt of 3??
OpenStudy (anonymous):
I differentiated the equation of the curve and replaced x with pi/6
OpenStudy (anonymous):
what did you get for the slope??
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
im confused
OpenStudy (anonymous):
can you show me how you got m=sqrt of 3
OpenStudy (anonymous):
4=sqrt3(pi/6)+c ??
OpenStudy (anonymous):
you would have to know the basic differentials...
\[y = \sin x \] \[\frac{ dy }{ dx } = \cos x\]
\[y = \cos x \] \[\frac{ dy }{ dx } = - \sin x\]
\[y = \tan x\] \[\frac{ dy }{ dx } = \sec ^{2}x\]
OpenStudy (anonymous):
yes..
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
are you ok with how i got the sqrt 3??
OpenStudy (anonymous):
no
OpenStudy (anonymous):
you can post that as a question because i use a shortcut method which i suppose would not be good for you....
OpenStudy (anonymous):
ok so you replaced sin x with cos x which is sqrt of 3/2
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes....and you would have to know that if you differentiate a constant standing on its own you get zero...
OpenStudy (anonymous):
yes i understand
OpenStudy (anonymous):
ok....but i advice you would have to work on it...(on the topic differentiation)
OpenStudy (anonymous):
so what does c equal
OpenStudy (anonymous):
so have you found c??
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
y-4=sqrt3(x-pi/6)
OpenStudy (anonymous):
if i have 4=sqrt3/6+c
OpenStudy (anonymous):
no.....
\[4 = \sqrt{3} (\frac{ \pi }{ 6 }) + c\]
OpenStudy (anonymous):
so you subtract 4-sqrt3(pi/6)
OpenStudy (anonymous):
yes...
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
are you supposed to leave your values in exact form or in decimals???
OpenStudy (anonymous):
exact form
OpenStudy (anonymous):
so what did you get as the value of c??
OpenStudy (anonymous):
3
OpenStudy (anonymous):
that would be a decimal
Still Need Help?
Join the QuestionCove community and study together with friends!