Question

e^x^2=e^12x times (1/(e^27))
what is the solution
x=______________

Answer 1

\[e ^{x ^{2}}=e ^{12x} \times \frac{ 1 }{ e ^{27} }\]

Answer 2

right side = e ^(12x -27) do you agree with me?

Answer 3

okay but what happens to the 1

Answer 4

hey, it's multiplication, not addition.!! I multiply them.

Answer 5

oh okay

Answer 6

good, now both sides is exponential of e , take e out, you have x^2 = 12x-27 ---> x^2 +12x+27=0. solve as usual to get x

Answer 7

so the answer would be -3 and -9

Answer 8

yes, sorry, you are right, negative

Answer 9

oh nvm its x^2-12x+27 so you are actually right

Answer 10

both us confused. do what you believe in.

Answer 11

you move the 12x and -27 to the x^2 side so it makes 12x into -12x and -27 to 27
so making it x^2-12x+27 and the fraction would be (x-9)(x-3) and the zeros would be 3 and 9

Answer 12

yes.

Answer 13

lol got confuse when you put a pos. 12 instead of a neg 12.
thank you!