Question

Find dy/dx of:

Answer 1

Y= integral of 1/t of dt where x>o from 1 to x

Answer 2

you mean:
\[\frac{d}{dx}\left[ \int\limits \frac{dt}{t}\right]\]

Answer 3

sry, forgot integration limits:
\[\frac{d}{dx}\left[\int\limits_0^x\frac{dt}{t}\right]\]

Answer 4

this?

Answer 5

if that's it, then dy/dx=1/t, by mane theorem of calculus

Answer 6

No, I mean dy/dx of y= (integral) (upper limit is 1, lower limit is x) then the equation of (1/t) with respect to t

Sorry I can't do an integral sign from where I'm typing this

Answer 7

And oh

Answer 8

\[\int\limits_x^1=-\int\limits_1^x\]
so answer is -1/t