Question

Given: a and B are first-quadrant angles, sin a=5/13, and cosB= 3/5. evaluate sin(a-B).

a.) -33/65
b.) 33/65
c.) 63/65

Answer 1

Use this here
\[\sin (A-B)=\sin A\times \cos B-\sin B\times \cos A\]

Answer 2

sin a=5/13, and cosB= 3/5

Answer 3

I tried this but the book is asking me to subtitute pi/2 for a

Answer 4

and I know I have to solve for sin B and cos A

Answer 5

\[\sin (B)=\cos (\frac {\pi}{2} -B)\]
\[\cos A=\sin (\frac{\pi}{2}-{A})\]
you can use
\[\sin^2 x+\cos^2 x=1\]
to figure out sin B and cos A

Answer 6

ok ill try this

Answer 7

cos a= 12/13

Answer 8

correct :)