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The radius of a sphere is increasing at a rate of 4 mm/s. How fast is the volume increasing when the diameter is 80mm?
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well isn't this a case of \[\frac{dV}{dt} = \frac{dV}{dr} \times \frac{dr}{dt}\] \[V = \frac{4}{3} \pi r^3....so.... \frac{dV}{dr} =4\pi r^2\] then \[\frac{dV}{dt} = 4\pi r^2 \times 4\] now substitute r = 40 and find the rate of change in the volume with respect to time.
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