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Mathematics 20 Online
OpenStudy (anonymous):

Help with simplifying expression. Assuming all variables are real numbers

OpenStudy (anonymous):

\[\sqrt[3]{27(x+4)^{3}}\]

OpenStudy (saifoo.khan):

\[\Large \sqrt[3]{27(x+4)^3} \to \sqrt[3]{27} \times \sqrt[3]{(x+4)^3} \]

OpenStudy (saifoo.khan):

Can you solve now?

OpenStudy (goformit100):

Yes

OpenStudy (anonymous):

Can you show me how to solve for it?

OpenStudy (saifoo.khan):

We just have to simplify it.

OpenStudy (saifoo.khan):

3*3*3 = 27 SIMILARLY cuberoot(27) =3

OpenStudy (saifoo.khan):

And cuberoot[(x+4)^3] = x+4 3 and 3 cancel out. So now you're only left with 3 and (x+4) Hence: 3(x+4) is your answer. Simplify it to get: 3x+12

OpenStudy (anonymous):

I'm confused, why do the 3's cancel out?

OpenStudy (saifoo.khan):

\[\Large \sqrt[3]{a^3} \to a^\frac33 \to a^1 \to a\]

OpenStudy (anonymous):

ahhhh ok!

OpenStudy (anonymous):

Thank you for laying it all out for me to understand

OpenStudy (saifoo.khan):

You're welcome.

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