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Help with simplifying expression. Assuming all variables are real numbers
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\[\sqrt[3]{27(x+4)^{3}}\]
\[\Large \sqrt[3]{27(x+4)^3} \to \sqrt[3]{27} \times \sqrt[3]{(x+4)^3} \]
Can you solve now?
Yes
Can you show me how to solve for it?
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We just have to simplify it.
3*3*3 = 27 SIMILARLY cuberoot(27) =3
And cuberoot[(x+4)^3] = x+4 3 and 3 cancel out. So now you're only left with 3 and (x+4) Hence: 3(x+4) is your answer. Simplify it to get: 3x+12
I'm confused, why do the 3's cancel out?
\[\Large \sqrt[3]{a^3} \to a^\frac33 \to a^1 \to a\]
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ahhhh ok!
Thank you for laying it all out for me to understand
You're welcome.
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