solve y'=2t+3y
rearrange it: \[\Large y'-3y=2t \] Looks like a known DE to you?
i did then i got answer -2/3t-2/9 i want to know if it is correct
wat for y'=t+siny
well your answer should be a function, also I believe that your answer is going to include an exponential function.
\[\Large \frac{d(ye^{-3t})}{dt}=2t \]
thx i got it do i use the same method for the second one y'=t+siny
Are you sure you have written it out right? sin is a function of y? or is it sin(t)y ?
no its sin y
seems strange to me, that would be a very hard differential equation, it's not linear.
that y im stuck coz im unable to solve it as sin is a function of y
have you done non-linear DE's yet? Because if not, then I believe this is a printing error.
non-linear DE's are always hard to solve, for this I guess using a Maclaurin Series would work well, or use advanced guess/Laplace.
yep i think u right as this is part of question on forward euler method, i need to integrate to get the exact value... n crap im stuck with the integration...
The Euler method can be used to approximate a solution, the only thing I can recommend to you is to read the DE like that: \[\Large y'=2t+\sin(t)y \] Now this DE can easily be solved with the same method as above, it's linear. Unlike this one: \[\Large y'=2t+\sin(y) \] However, if you need to approximate one special solution near a given value, you can try it with the Euler Method.
in fact i need to find the error so have already done the euler method so now i think i will use the sin(t)y so that i can get the exact value n complete my exercise... thx lots for the help.. r u student also?
Yes student of Mathematics
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