Question

In the following unbalanced equation, how many moles of nitrogen monoxide are needed to react with excess ammonia to produce 32.6 grams of water?
NH3 + NO --> N2 + H2O

Answer 1

Start by balancing the equation.

Answer 2

Just follow the general guide for stoichiometry. :)

Answer 3

4 NH3 + 6 NO --> 5 N2 + 6 H2O

Answer 4

Now use the relation for the number of moles you have by a given mass.

Answer 5

32.6 g H2O/ 18 g H2O = 1.81 mol
1.81 mol H2O * 6 mol NO / 6 mol H2O?

Answer 6

Is 1.81 the correct answer?

Answer 7

It sure is. :)

Answer 8

By just looking at it

Answer 9

Okay, well thank you for your help :)

Answer 10

No problem at all... you did it all by your self :)

Answer 11

Which is the best ever!

Answer 12

Do you think I'd have to take the molar mass of 6 moles of H2O? Or is what I did okay?

Answer 13

The 18 g/mol is molar mass? just need to get the units right.

Answer 14

M(H2O)=2*1 g/mol + 16 g / mol = 18 g/mol

Answer 15

18 grams was just the mass of 1 mole of H2O, do you think I did it right?

Answer 16

Well... best you use the unit g/mol as I showed in the calculation.. then your units go perfect :)

Answer 17

\[n(H _{2}O)=n(NO)\]
\[n(NO)=n(H _{2}O)=\frac{ m(H _{2}O )}{ M(H _{2}O) }\]
\[M(H _{2}O)=2*M(5)+M(O)=2*1+16=18 g/mol\]
\[n(NO)=\frac{ 32.6 g }{ 18 g/mol }=1.81 mol\]

Answer 18

sorry meant:
\[M(H _{2}O)=2*M(5)+M(O)=(2*1+16) g/mol=18 g/mol\]

Answer 19

Thank you so much! I really appreciate this :)

Answer 20

lol and not M(5) but M(H) xD

Answer 21

You're right, though! The units cancel perfectly. I forgot to write mine that way.

Answer 22

But glad you appreciate it... science teachers love when the units along with the calculations are good :)

Answer 23

Very true! Thank you again :)

Answer 24

No problem at all.