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Evaluate 3-i / 6+6i
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first rationalize the denominator i.e., \[\frac{3-1}{6+6i}\times\frac{6-6i}{6-6i}\]
this step will remove the imaginary part from the denominator
yes which brings me to \[12-25i \div 6^2 - (6i)^2 \] now i need help to see what i am mistaking?
correct
the bottum equals 72 ?
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numerator: \((3-i)(6-6i)=18-6i-18i-6\)
yes bottom is 72 but your numerator is wrong
oh... wait ... i see what i did .... so the numerator is .... 12-24i
right
lol life saver !! THANK YOU :}
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you are welcome
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