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Find the solution: -3 sin^-1 (2x) = π
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can you isolate sin^-1 (2x) first ?
It equals -π/3?
yes, now if \(\sin^{-1}a=b, \implies a=\sin b\) so, what can you say baout sin^-1 (2x) =-pi/3 ?
sin(π/3)=2x?
what about -*minus* sign ? why did you just drop it ? :P
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won't it be sin(-π/3)=2x
Oops, I forgot it, sorry! sin(-π/3)=2x
you can now use \(\sin (-\theta )=-\sin \theta\) to get -sin(π/3)=2x got this ? and whats sin (pi/3)=...?
I'm not sure, would it be √3)/2?
yes, thats correct. so, -(√3)/2=2x i believe you can find 'x' from here easily :)
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You get -((√3)/4)?
thats correct value of x :)
Thank you again! (:
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