Question

Find all solutions in the interval [0,2pi) for sin2x + sqr(3)cosx = 0

Answer 1

\[Sin2x + \sqrt{3} cosx=0\]

Answer 2

replace sin2x with 2sinxcosx and factor out cosx

Answer 3

so it would be \[cosx (2sinx + \sqrt{3})\]? @Mertsj

Answer 4

yes

Answer 5

Now solve each factor separately. \[\cos x=0\]and\[\sin x=\frac{-\sqrt{3}}{2}\]

Answer 6

thanks :) i finished