Question

Question: calculus

Answer 1

for the first one, i got 14x/2x

Answer 2

It's increasing when \(f'(x)>0\) and decreasing when \(f'(x)<0\)

Answer 3

What is your derivative?

Answer 4

I got 14x/2x

Answer 5

No, you must use the quotient rule.

Answer 6

\[
(f/g)'=(f'g-fg')/g^2
\]

Answer 7

Ohhh!! I forgot about that

Answer 8

I got
\[\frac{ (7x^2)(2x)-(x^2+4)(14x) }{ (x^2+4)^2 }\]

Answer 9

I dont know if I should simplify?

Answer 10

You did the wrong derivatives...

Answer 11

It's close but the top terms are in the wrong order.

Answer 12

Then you gotta expand

Answer 13

\[\frac{ (14x)(x^2+4)-(7x^2)(2x) }{ (x^2+4)^2 }\]

Answer 14

Yeah. Now you want to expand the numerator (we don't worry about the denominator). We need to find the root of the numerator because it is the root of the whole thing.

Answer 15

\[\frac{ 56x }{ (x^2+4)^2 }\]i got

Answer 16

Is that after you expanded it?

Answer 17

yes.

Answer 18

Alright. So clearly the root for the numerator is \(0\)

Answer 19

root?　ok

Answer 20

Basically is it where \(f'(x)=0\)

Answer 21

ok,

Answer 22

what's next?

Answer 23

to find critical number?

Answer 24

We did...

Answer 25

Do i pulg some number to solve then , from that find out max and min?

Answer 26

Yeah

Answer 27

im confused what number?

Answer 28

@wio