If the accepted value for the heat of combustion for sugar is 5639 kJ/mol, calculate the percent error (Hint: the percent error must be no more than .35%)

Question

angelwings996 · Answer

$$%Error=\frac{ your answer-accepted answer }{ accepted answer } *100$$

anonymous · Answer

is that all? the question's incomplete.

angelwings996 · Answer

I did post the equation but It isn't showing up for me on here. Other than that yes, that is the full question

angelwings996 · Answer

I can try to tell the other questions that went along with this question, I'm not sure if I have the right answer though for two of them

anonymous · Answer

the first reply isn't showing. I see a blank reply.

angelwings996 · Answer

It is blank for me too: I was trying to say that the equation is

%Error=(your answer - accepted answer)/(accepted answer) *100

angelwings996 · Answer

I'm confused about the part where it says your answer. I don't know what answer it is talking about

anonymous · Answer

that's fine. All that's missing is "your answer". I'm assuming you have to do an experiment to find that out.

angelwings996 · Answer

Well, I had a question right before it where I had to find the heat of combustion for sucrose but I am not sure if I got it right considering that I don't get a percentage that is below .35%

anonymous · Answer

^there's your answer.

angelwings996 · Answer

What is my answer? The answer I got from the question before?

anonymous · Answer

no i mean, you have to find the correct (i.e. closest to correct) answer to the previous question first. And you use this question to just verify if your answer is correct/within the error range.

angelwings996 · Answer

Okay, but I don't know how to find the correct answer. I have tried it many times but never seem to get it right

anonymous · Answer

In that case, I can come in and help you only if you post the entire question.

angelwings996 · Answer

The question is:Delta H_comb for sucrose can be calculated by Delta H_comb = (C_system Delta T)/n, where n is the moles of sucrose in the sample and C_system is the heat capacity of the calorimetric system. Using the value you calculated for C_system, calculate the heat of combustion for sucrose.

angelwings996 · Answer

The moles is 0.0030236... DeltaT is 1.7

anonymous · Answer

"Using the value YOU calculated". That's where you may have gone wrong.

angelwings996 · Answer

and I believe where it says to use the value you calculated for C_system, it is referring to the question I did before for benzoic acid : Delta H_comb for benzoic acid can be calculated by Delta H=(C_system Delta T)/n, where n is the moles of benzoic acid in the sample and C_system is the heat capacity of the calorimetric system. If the accepted value for the heat of combustion for benzoic acid is 3226 kJ/mol, calculate the heat capacity (C_system) of the calorimetric system.

angelwings996 · Answer

Delta T for benzoic acid is 3 and the moles is 0.0074

angelwings996 · Answer

I am not sure if I did this question right either but I got an answer of C_system=0.1256

anonymous · Answer

that's way off.

angelwings996 · Answer

Yeah, I didn't know how to do it

anonymous · Answer

yeah i'm not sure how to do it too.

angelwings996 · Answer

How did you get 2?

anonymous · Answer

http://bit.ly/106frU4

angelwings996 · Answer

@TrashMan914 I know how to find one, I just got the two main questions wrong and now I am trying to find the correct answers to help me with this question

anonymous · Answer

@Preetha @aaronq