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how to integrate:
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\[\pi \int\limits y \sin^2(y) dy\]
You'd really want to use the double angular formula here for the sin^2(y) term
1/2 -1/2 cos 2y?
yes that's the one.
\[\pi \int\limits y (1/2 -1/2 \cos 2y) dy\]
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\[1/2 \pi \int\limits (y - ycos2y) dy\] i dont know that part: \[\int\limits y \cos 2y dy\]
Try integrating by parts!
\[1/4 \pi y^2- 1/4 \pi y siny - 1/8 \pi \cos 2y\] ?
That's right.
Oh, and it's sin(2y)!
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