Question

Determine the equation of the function that has the indicated transformation applied to the function f(x)= 3(x+1)^2 -2

Answer 1

a) translated up 2 and moved 2 units to the right

Answer 2

a. f(x)= 3(x+1)^2-2
=3(x+1+2)^2-2+2
= 3(x-3)+0

Answer 3

Can anybody tell me if this is correct?

Answer 4

b) reflected in the x-axis and strtched by a factor of 3.

Answer 5

b. f(x)= 3(x+1)^2-2
=-3(x+1+2)^2-2
= -6(x+2)^2-2

Answer 6

3(x+1)^2-2 = 3x^2+6x+1=
\[\frac{1}{3}\times3 \times (3x ^{2}+6x+1)= \frac{1}{3}\times ((3x)^{2}+18x+3) \]
\[\frac{1}{3}\times((3x+3)^{2}-6) = \frac{1}{3}(3x+3)^{2} -2\]

Answer 7

The vertex of the given function is (-1,-2) If you move it 2 right and 2 up the new vertex will be (1,0) and the equation will be: y= 3(x-1)^2+0

Answer 8

If you apply a stretch factor of 3 and reflect in the x axis the new equation is: y = -9(x+1)^2-2