Question

determine the vertex and the axis of symmetry for the fraction below y=-x^2+2x+1

Answer 1

vertex of a parabola \(y=ax^2+bx+c\) always has the first coordinate \(-\frac{b}{2a}\) which in your case is \(-\frac{2}{2\times (-1)}=1\)

Answer 2

second coordinate of the vertex is what you get when you replace \(x\) by \(1\)

Answer 3

So the vertex s is -1 2 and the symmetry is x=1

Answer 4

no the first coordinate of the vertex is \(1\) not \(-1\)

Answer 5

the axis of symmetry is \(x=1\) though, you are right for that one

Answer 6

and the second coordinate is 2 as you said

Answer 7

see attachment

Answer 8

Thank you

Answer 9

it is \((1,2)\) but all else is right
yw