how do i find an inverse trig angle that is not on the unit circle and without using a calculator. For example: arcsec(3/5) = ?
well this is a really bad example but here is the logic \[\sec = \frac{1}{\cos}\] so the question is really saying \[\sec(x) = \frac{3}{5} \] or \[\frac{1}{\cos(x) }= \frac{3}{5} \] take the reciprocal of both sides \[\cos(x) = \frac{5}{3}\] now you could find the angle by unfortunately it doesn't exist... since the cos of an angle is always less than 1. so before finding x = arcsec(5/3) use some basics. sec(x) = 5/3 cos(x) = 3/5 x = arccos(3/5) this would work.
Thanks, but then how would you find x = arccos(3/5) with no calculator and no unit circle
well one method would be approximate \[\cos(45) = 1/\sqrt{2} = 0.707\] cos(60) = 1/2 so arccos(0.6) is about half way between the 2 angles 45 and 60... so approximate it at 52.5 degrees. or maybe 53 use the exact values to help approximate
you also know the values for sin, cos and tan of 0 degrees, 30 degrees and 90 degrees... the will assist in approximating. Thats my best idea... other than looking at a trig table.
Thank you campbell, but I still need to know without having to approximate.
In general, you need a calculator. There are only some small subset of angles that you can figure out using other methods.
first of all, the secant of an angle cannot be 3/5 because the secant is always greater than 1 or less than negative 1 so the answer to that question is does not exist.
Secondly, if you had the secant of an angle that did exist, let us say, perhaps, 5/3, you could draw the triangle and find all 6 functions of that angle but if you wanted the actual angle, you would need either a table of values or a calculator.
So you are telling me that for some sides you simply cannot find an actual angle without a calculator?
yes.
That's why, in the old days, before calculators, we used to carry books full of tables around with us.
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