Question

Anyone good at integration by parts please help

Answer 1

\[\int\limits_{}^{}xe ^{3x}dx\]

Answer 2

let:
\(u=x\) \(dv=e^{3x}dx\)
\(du=dx \) \( v=\frac{1}{3}e^{3x}\)
then:\[\int xe^{3x}dx=\frac{1}{3}xe^{e3x}-\frac{1}{3}\int\limits e^{3x}dx\]

Answer 3

can you finish this?

Answer 4

myko what is the additional term you have in front of the 3x exponent? Shouldn't it just be
\[\int\limits_- xe ^{3x}=\frac{ 1 }{ 3 }xe ^{3x}-\int\limits_{}^{}\frac{ 1 }{ 3 }e ^{3x}\]

Answer 5

oh ya. typo

Answer 6

ok just making sure i'm doing it right....lol....thanks

Answer 7

still not working

Answer 8

I got it sorry, just get too frustrated too easily

Answer 9

answer is:
\[\frac{1}{3}xe^{3x}-\frac{1}{9}e^{3x}\]