how do you do this
If the height of the cone is 5 and the base radius is 4, write a parameterization of the cone in terms of r=s and θ=t.
x(s,t)= ,
y(s,t)= , and
z(s,t)= , with
≤s≤ and
≤t≤ .
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OpenStudy (dan815):
@wio
OpenStudy (anonymous):
|dw:1364240753122:dw|
Like this?
OpenStudy (dan815):
|dw:1364240790153:dw|
OpenStudy (anonymous):
Alright.
OpenStudy (anonymous):
Okay so first lets do \(z\) cause it is easiest. We want to convert the radius to height.
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OpenStudy (anonymous):
We have two points: \((s,z)=(0,5)\) and \((s,z)=(4,0)\)
OpenStudy (anonymous):
The equation of a line that goes through the points \((x_1,y_1)\) and \((x_2,y_2)\) is given by: \[
y-y_1 = \frac{y_2-y_1}{x_2-x_1} (x-x_1)
\]
OpenStudy (anonymous):
Use this if formation to find \(z(s)\)
OpenStudy (anonymous):
\(z(s,t)=z(s)\) since \(z\) will be constant with respect to \(t\).
OpenStudy (anonymous):
We also know that \(0\le s \le 4\)
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OpenStudy (anonymous):
@dan815 You following me?
OpenStudy (dan815):
ya im reading
OpenStudy (dan815):
i dont understand that equation of a linne
OpenStudy (dan815):
will i get the same answer with y = mx+b
OpenStudy (dan815):
oh nvm now i see go on
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OpenStudy (anonymous):
Basically \(z(s,t)\) is a line. \(z(s,t)=ms+b\)
OpenStudy (anonymous):
So can you find \(z\) to start with?
OpenStudy (dan815):
so (5/-4)x + 5?
OpenStudy (anonymous):
yes, but not \(x\), it's \(s\)
OpenStudy (dan815):
right
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OpenStudy (anonymous):
do you remember the parametrization of a circle?
OpenStudy (dan815):
x^2+y^2 = 16?
OpenStudy (dan815):
sintheta^2+cos^2
OpenStudy (dan815):
sin(t)^2+cos(t)^2=16 to sin(t)^2+cos(t)^2=0
OpenStudy (anonymous):
It's \((x(t), y(t)) = (\cos(t),\sin(t))\)
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OpenStudy (dan815):
how do u write an equation where that circle is decreasing as z increases
OpenStudy (anonymous):
But this is for the unit circle, if you want it to have radius \(s\), we multiply that in: \[
x(s,t)= s\cos(t)\\
y(x,t)=s\sin(t)
\]
OpenStudy (anonymous):
\[
x(s,t)= s\cos(t)\\
y(s,t)=s\sin(t)
\]
OpenStudy (dan815):
why does that work
OpenStudy (anonymous):
Remember the \(z\) changes is because \(s\) that is increasing.
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OpenStudy (anonymous):
It works because of the equation of a circle: \[
x^2+y^2= r^2 \\
[s\cos(t)]^2+[s\sin(t)]^2=r^2\\
s^2\cos^2(t)+s^2\sin^2(t)=r^2\\
s^2(\cos^2(t)+\sin^2(t))=r^2\\
s^2= r^2
\]
OpenStudy (dan815):
ok gotcha
OpenStudy (dan815):
thanks
OpenStudy (anonymous):
Remember the bounds of \(s\) and \(t\)
OpenStudy (dan815):
0 - 4 and 0-2pi
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