What are the minimum, first quartile, median, third quartile, and maximum of the data set? 9, 20, 4, 18, 4, 18, 20, 9 A. minimum 4; first quartile 10; median 16.25; third quartile 19.5; maximum 20 B. minimum 4; first quartile 6.5; median 13.5; third quartile 19.5; maximum 20 C. minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20 D. minimum 4; first quartile 5.25; median 16.25; third quartile 19; maximum 20
I'm only confused about the 1st and 3rd quartile
@amistre64 Can you please explain this for me please?
whats your median?
also, put your data in order to help see it better
quartiles suggest quarters, or divide by 4 take the number of data points you have and divide by 4, then multiply that value by 0,1,2,3,4 to get the quartiles
IF the quartiles have a decimal, round up IF the quartiles are integers, youll have to average the positions
My median is 13.5 and when I put them in increasing order I got 4, 4, 9, 9, 18, 18, 20, 20 and I don't understand what you're saying on how to solve the quartiles, I'm lost o.o
lost please explain
generally, a quartile is a positional value. you have 8 numbers, or positions to choose from a quartile is a division into quarters, or /4 8/4 = 2 is your basic quartile value. Q0 = 0*2 = 0 Q1 = 1*2 = 2 Q2 = 2*2 = 4 Q3 = 3*2 = 6 Q4 = 4*2 = 8 the values here relate to POSITIONS in the ordered set of data
the trouble here is that all the values are integers, no decimals so we have to average them out with their next highest position
Q1 for example is the average of the 2nd and 3rd positions 4, 4, 9, 9, 18, 18, 20, 20 2 3 ^^^^ 4+9 = 13/2 = 6.5 Q2 is the average between the 4th and 5th postiions 4, 4, 9, 9, 18, 18, 20, 20 4 5 ^^^^ 9+18 = 27/2 = 13.5 can you find Q3 for me?
Uhmmm is it 18 + 20 = 38/2 = 19 ?
yes :)
Yayyyyy, thank you lol
youre welcome, and make sure you pick C ;)
Lol [x thank you, will do.
Join our real-time social learning platform and learn together with your friends!