Question

Chem 2 help!
1) write Kc and Kp form if applicable
2) write it backwards. (I guess she means the reverse form)
a)HF(aq) + H2O(l) <--> H3O+(aq) + F-(aq)
b) 2NO(g) + O2(g) <--> 2NO2(g)
c)) CH3COOH(aq) + C2H5OH(aq ) <--> CH3COOC2H5(aq) + H2O(l)

I understand how to get Kc and Kp if applicable. But I am not understanding how I would "write it backwards". The teacher told us something about the backwards form being: K (-1)=(1/k)

so would that mean K(-1)=(1/Kc) and (1/Kp)?? o.O Please can someone shed some light? :O Please and thank you!

Answer 1

see u should find Kc for the non gaseous reaction and Kp for the gaseous reactions

Answer 2

KC is = Products / reactants
this is for forward reaction
if you want to write ir for backward reaction then it becomes
KC' =Reactants/ products
=1/Kc

Answer 3

for example
)HF(aq) + H2O(l) <--> H3O+(aq) + F-(aq)
Kc= [H3O] [F-] / [H2O] [HF]
this is equilibrium constant for forward reaction
now let us right for the backward reaction
Kc' =[H2O] [HF] / [H3O] [F-]
=1/ [H3O] [F-] / [H2O] [HF]
=1/Kc
Kc = equllibrium constant for forward reaction
Kc' =equilibrium constant for forward reaction

similarly you can do for other reaction

Answer 4

Ok, that makes sense! So this only applies to Kc?

Answer 5

no you can do for Kp tooo Kp' =1/Kp

Answer 6

Kc' =equilibrium constant for forward reaction
in the above answer please change forward reaction to backward reaction
by mistake i wrote it as forward reaction

Answer 7

Kc' =equilibrium constant for backward reaction
it should be!!!:)