√x +√y * dy/dx = 0 when y(1)=4. Find the solution of the differential equation that will satisfy the condition. Differential equations. I understand how to separate the variables, but I'm not sure where/when it might make sense to square the equation to get rid of the square roots.
Usually you do that when you try to solve for y explicitly.
Meaning?
Separate your variables, integrate normally, solve for y (don't forget that you'll have a constant), apply your initial conditions to solve for that constant, done.
So I got √y * dy = -√x * dx then I integrated and got (2y^(3/2))/3 = (-2x^(3/2))/3 Is that correct so far?
yes, don't forget the constant. The constant here for you to find the particular solution in addition to general solution
So the integration is correct and now I added C to to the right side of the equation and now I need to substitute 1 in for x and solve??
i didnt look at your integration. But, the steps are correct. Yes
My integration might be wrong xD. Or at least I'm about it.
ugh
sorry right
(GAH!!) So where'd I go wrong?
did u substitute y=4 x=1, or where exactly u got wrong?
I didn't substitute in y=4 x=1 until after integration.
do have answer?
I don't have the integration right though.
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