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Calculus1 15 Online
OpenStudy (anonymous):

√x +√y * dy/dx = 0 when y(1)=4. Find the solution of the differential equation that will satisfy the condition. Differential equations. I understand how to separate the variables, but I'm not sure where/when it might make sense to square the equation to get rid of the square roots.

OpenStudy (anonymous):

Usually you do that when you try to solve for y explicitly.

OpenStudy (anonymous):

Meaning?

OpenStudy (anonymous):

Separate your variables, integrate normally, solve for y (don't forget that you'll have a constant), apply your initial conditions to solve for that constant, done.

OpenStudy (anonymous):

So I got √y * dy = -√x * dx then I integrated and got (2y^(3/2))/3 = (-2x^(3/2))/3 Is that correct so far?

OpenStudy (anonymous):

yes, don't forget the constant. The constant here for you to find the particular solution in addition to general solution

OpenStudy (anonymous):

So the integration is correct and now I added C to to the right side of the equation and now I need to substitute 1 in for x and solve??

OpenStudy (anonymous):

i didnt look at your integration. But, the steps are correct. Yes

OpenStudy (anonymous):

My integration might be wrong xD. Or at least I'm about it.

OpenStudy (anonymous):

ugh

OpenStudy (anonymous):

sorry right

OpenStudy (anonymous):

(GAH!!) So where'd I go wrong?

OpenStudy (anonymous):

did u substitute y=4 x=1, or where exactly u got wrong?

OpenStudy (anonymous):

I didn't substitute in y=4 x=1 until after integration.

OpenStudy (anonymous):

do have answer?

OpenStudy (anonymous):

I don't have the integration right though.

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