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Physics 6 Online
OpenStudy (anonymous):

Calculate the total heat content of 10 kg of ice at -23°C. (Hint: absolute zero is -273°C.)

OpenStudy (anonymous):

I'm assuming what they mean by this question is what is the maximum amount of heat that this block of ice can transfer? (Heat is strictly energy moving from an object of high temperature to an object of lower temperature.)

OpenStudy (anonymous):

how would i solve .

OpenStudy (anonymous):

Okay, well, heat is a form of energy, and has it's own equation to find it \[Q=mc \Delta T\] Where Q = heat m = mass c = specific heat Delta T = change in temperature (T(f) - T(i)) So, do you know the specific heat of ice?

OpenStudy (anonymous):

0.50

OpenStudy (anonymous):

Hmm, I don't believe that is correct. This value is usually something that you would just look up in a table so not that important to memorize. \[\Large c_{ice}=2108\frac{J}{kg*K}\] Since we are dealing with change in temperature here and The Celsius scale is just K+273, we can leave the temperature in Celsius and it won't matter, the change will be the same. So we are solving for Q, we know m, c, and delta T, so we have:\[Q = mc(T_{f}-T_{i})\] What are your final and initial values for temperature?

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