Mathematics
8 Online
OpenStudy (anonymous):
Find the indicated limits.
lim x ->-2 x + 2/x^2 - 4
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OpenStudy (anonymous):
@electrokid can u help?
OpenStudy (anonymous):
could you rewrite it using the equation editor
OpenStudy (anonymous):
yes hold on
OpenStudy (anonymous):
factor, and cancel
then replace \(x\) by \(-2\)
OpenStudy (anonymous):
\[\lim_{x \rightarrow -2} x + 2/x^2 - 4 \]
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OpenStudy (anonymous):
hmm you mean
\[\lim_{x\to-2}\frac{x+2}{x^2-4}\]
can we factor the denominator?
\(a^2-b^2=(a+b)(a-b)\)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[\lim_{x\to-2}\frac{x+2}{(x+2)(x-2)}\]
OpenStudy (anonymous):
now, since \[x\to-2,\quad x+2\ne0\]
and hence can be cancelled from numerator and denominator
OpenStudy (anonymous):
\[\lim_{x\to-2}\frac{\cancel{x+2}}{\cancel{(x+2)}(x-2)}=\lim_{x\to-2}\frac{1}{x-2}\]
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
now, you can substitute the value fr "x"
OpenStudy (anonymous):
okay :)
OpenStudy (anonymous):
so its 1/-4
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
you can only cancel the factors if they are not zero
OpenStudy (anonymous):
okay thanks
OpenStudy (anonymous):
okay thanks
OpenStudy (anonymous):
Hey can u help me with this one Find the indicated limit
limx->infinity (e^2x - 1)/(x)
OpenStudy (anonymous):
are u there?
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OpenStudy (anonymous):
are u there?