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Find an equation in standard form for the hyperbola with
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Well, I see the center is at the origin, do you see that?
Yes
Is a=3 and b=4?
We know the vertices so we can find a
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Yes. a = 3, = 4
b=4, I meant
Ok, I got that from the asymptote
Very good.
So this is a vertical hyperbola
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yes
So is the equation y^2/9 - x^2/16 = 1 ?
We have to be careful here because from the asymptotes, it looks like a = 3 and b = 4 but it tells us the vertices are (0,6) and (0,-6) so we know that a is really 6 and the equations of the asymptotes before they reduced the fraction were y =( 6/8)x and y = (-6/8)x
Ohhhh
I knew something was weird
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So the equation is?
So it's y^2/36 - x^2/64 = 1 ?
Perfect!!
Thanks!! You rock!
ty and yw
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