Question

PLEASE CAN YOU HELP ME? I'm stuck

Simplify the radical expressions

sqrt 7 (sqrt 14 + sqrt 3)

sqrt 45n^5

Answer 1

on the first one I got until here

sqrt 7 * sqrt 14 + sqrt 7 * sqrt 3

sqrt 7 * sqrt 7x2 + ......

Answer 2

and on the second one until here:
sqrt 5*9*n^2*n^2*n =
sqrt 5 * sqrt 9 * sqrt n^2 * sqrt n^2 * sqrt n

Answer 3

the 1st question is simply

\[\sqrt{7} \times \sqrt{14} + \sqrt{7} \times \sqrt{3} = \sqrt{ 7 \times 14} + \sqrt{7 \times 3}\]

you need to simplify it

the 2nd question

\[\sqrt{45n^5} = \sqrt{9n^4 \times 5n} = \sqrt{9n^4} \times \sqrt{5n}\]

just simplify

Answer 4

so on the fist one was I right?

Answer 5

I just missed the sqrt 7x3 right?

Answer 6

going back to the 1st question

\[\sqrt{7 \times 14} = \sqrt{98} = \sqrt{49 \times 2}\]

which can be simplified.

Answer 7

into... sqrt 7x2 ?

Answer 8

well \[\sqrt{49} \times \sqrt{2} = 7\sqrt{2}\]

so the 1st question is

\[7\sqrt{2} + \sqrt{21}\]

the 2nd question

\[\sqrt{9n^4} \times \sqrt{5n} = 3n^2\sqrt{5n}\]

hope this makes sense.

Answer 9

second question final form. is it.
\[3n ^{2} \sqrt{5n}\]

Answer 10

oh! ok I busy making the equation haha

Answer 11

yes on the second yes it does

Answer 12

glad to help

Answer 13

oh ok! got the firt one

Answer 14

thank you very much!