derivative application....

Water is flowing into a spherical tank with 6 ft radius at constant rate of 30pi cu ft per hr. When the water is h feet deep, the volume of water is given by
V=((pih^2)/3)*(18-h)
What is the rate at which the depth of the water in tank is increasing at the moment when the water is 2 ft deep?

Question

derivative application....

Water is flowing into a spherical tank with 6 ft radius at constant rate of 30pi cu ft per hr. When the water is h feet deep, the volume of water is given by
V=((pih^2)/3)*(18-h)
What is the rate at which the depth of the water in tank is increasing at the moment when the water is 2 ft deep?

anonymous · Answer

$$V=\frac{ \pi h^2}{ 3 }(18-h)$$

anonymous · Answer

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