Question

State the vertical asymptote of the rational function.

f(x)=(x-3)(x+4)/x^2-1

Answer 1

how do we find a vertical asymptote?

when the denominator = 0....that makes it

so when does x² - 1 = 0?

Answer 2

when x = 0?

Answer 3

that's....a start....remember x is squared....so what else can it be?

Answer 4

for this particular problem....there will be 2 vertical asymptotes...because x² - 1 = 0 has 2 answers

Answer 5

and you deleted your answer of x = 1....that was a correct answer

Answer 6

oh, sorry, only because I put w=1, I was going to retype it, but i had to take my dogs out

Answer 7

Are you there?

Answer 8

sorry about that...yes.....and yes okay so x = 1 is an answer

how else can x² - 1 = 0?
we know that
1² - 1 = 0 right? as you stated

what else can be ² to make 1?

Answer 9

-1?

Answer 10

correct! :)

so your 2 answers would be

a vertical asymptote at 1, and -1

Answer 11

Oh, And that's it?

Answer 12

Thanks:)

Answer 13

that's all it's asking for is to find the vertical asymptotes....so that would be it :)