State the horizontal asymptote of the rational function. f(x)=x^2+4x-7/x-7
horizontal asymptotes are a bit different where does this equation approach....when x is set to infinity? focus only on x²/x so imagine infinty ² / infinity what does this equal?
Ummmm...Infinity?
correct! I know don't let it confuse you....it really is that simple :)
so....realistically....where would you see a horizontal asymptote? at infinity? where would you graph infinty? you wouldn't.....so for this example.....there is no horizontal asymptote....but if there was one...it would be at infinity
Okay:) Thanks much:)
I hope that made sense??
Not entirely, but next time I have a question I can just look back on this to see if it will help.
lol okay...but to make it clear infinity² / infinity = infinity.....a.k.a NO HORIZONTAL ASYMPTOTE now imagine x / x set those both to infinity you have infinity / infinity....= ...1 right? any number divided by itself is 1....for this kind of problem...you would have a horizontal asymptote at 1 now imagine x / x² set THOSE both to infinity infinity / infinity ² since the denominator grows faster than the numerator....the number gets SMALLER and SMALLER until it approaches 0 imagine 1/10....then 1/100,...then 1/1000.....1/10000000000 gets smaller and smaller of an answer right? same thing....for bigger and bigger numbers that you put for x...the answer would get smaller so in THAT case.....x / x² approaches 0.....so it would have a horizontal asymptote at 0
hopefully THAT helps :)
Yea, That helps more:) Thanks:)
anytime :)
But what if you have something like 9x^2/ 4x^2?
oh and to clarify 1 more thing when I said "only focus on x² and x imagine you have 100000000000000000000000.......+ 4x + 3 those 4x and 3....dont do much to add to this number right? so we ignore them...we focus ONLY on the higest degree terms.....but okay....your next question...
so we have 9x² / 4x² (thank you for pointing out that I missed a part :)) 9x² / 4x² remember when I said x / x ....would be 1? so 9x² / 4x² the x² and x² go to 1 so all you have is 9/4
Well the full problem is f(x)=9x^2-3x-8/4x^2-5x+3, do you still only focuse on the 9x^2/4x^2?
because remember....technically you are dividing so 9x² / 4x² x² / x² no matter WHAT x is....will equal 1 right? so all you'll have is 9/4 left......hang on lemme see what you just said
you are correct :) you only focus on the highest degree terms in the numerator and denominator
Okay, It just confused me that you have this long equation and you only focuse on the first part of it.
yeah I know...but like I said....imagine you have 10000000000 + some small number + some other small number........ those small numbers barely make ANY difference....so you ignore then when infinity is involved
Okay, I get it now. Thanks so much for your help:)
glad you understand it :) anytime :)
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