Suppose you roll two number cubes and pick a letter of the alphabet at random. Find the probability you roll 2 even numbers and pick one of the vowels a, e, i, o, or u. A. 7/104 B. 5.104 C. 1/6 D. 1/104
Hint: assuming the events are independent, you would multiply out the probabilities
P(even number, even number, vowel) = P(even number)*P(even number)*P(vowel)
its 1/104
P(even number) = ???
There are 3 even numbers (2,4,6) Out of 6 total (1,2,3,4,5,6) So... P(even number) = ???
oh its 1/12
wait that's not right
even number is 12
if you roll the die, what's the probability of rolling an even number?
keep in mind that 3 out of the 6 numbers are even
it's not 1/12
so then its 1/6
yes
Thank you all :)
P(even number) = 3/6 P(even number) = 1/2
P(vowel) = 5/26
P(even number, even number, vowel) = P(even number)*P(even number)*P(vowel) P(even number, even number, vowel) = (1/2)*(1/2)*(5/26) I'll let you multiply it out The answer is NOT 1/6
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