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Mathematics 20 Online
OpenStudy (anonymous):

(x) = 3x + 9, g(x) = 3x2 Find (fg)(x).

OpenStudy (anonymous):

9x^(3) + 27x^(2) ?

OpenStudy (anonymous):

prob what u meant is \[(f \circ g)(x)\] in that case, means the variable x in the f(x) is now defined as a function of g(x), for simplicity, substitute x in the f(x) by g(x). Thus, \[f(x)=3x+9\] then \[(f∘g)(x)=3[3x^2]+9\] ...since i assume your \[g(x)=3x^2\] . First it's very confusing, but if you work on more problem, it becomes more make sense. NOw just challenge yourself with \[(g∘f)(x)\]

OpenStudy (anonymous):

thanks guys

OpenStudy (precal):

just like San2 stated above

OpenStudy (anonymous):

Thanks!

OpenStudy (precal):

correction: (fg)x means f(x) times g(x) this is not a composition of functions

OpenStudy (precal):

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OpenStudy (precal):

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OpenStudy (precal):

you were actually correct, I am sorry to mislead you......

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