The probability that Shania is on time for school is 1/2. Find the probability that Shania arrives on time for school for the next 5 days. Express your answer as a percent, to the nearest tenth of a percent. A. 50% B. 15.6% C. 11.4% D. 3.1%
well....she has a 50% chance of getting to school on time on any given day....so the percent wont change no matter how many days she goes....she will always have a 50% chance of getting to school on time....in 5 days....she has a (50% + 50% + 50% + 50% + 50%) / 5 50%
Thanks
Using the binomial distribution the proability of arriving on time for the next 5 days is \[P(5\ days\ on\ time)=(0.5)^{5}=.03125\] This probability rounded is 3.1%
probability*
I guess I was wrong....thanks @kropot72 havent done probabilities in a while
You're welcome :)
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