Question

solve for x/3+5/2=10

Answer 1

solve for \(x\)?

Answer 2

if so,

\[{x\over3}+{5\over2}=10\]get common denominators \((6)\):\[{2x\over6}+{15\over6}={60\over6}\]the denominators no longer matter:\[2x+15=60\]solve for x, subtract ](15\) from both sides:\[2x=45\]isolate the \(x\), divide both sides by \(2\):\[x={45\over2}\] or if you want it in decimal form:\[x=22.5\]

Answer 3

x/3+5/√2=10 solve for x plz

Answer 4

\[\large{{x\over3}+{5\over\sqrt{2}}}=10~??\]

Answer 5

yes

Answer 6

solve in simplest form not decimal plz

Answer 7

follow the same steps as i gave above

Answer 8

what do i do with the square root

Answer 9

hint: the common denominator is \(3\sqrt{2}\)

Answer 10

multiple by square root of 2?

Answer 11

either way

Answer 12

can you show me

Answer 13

quickly

Answer 14

like first step .. what i should do

Answer 15

\[{x\sqrt{2}\over3\sqrt{2}}+{15\over3\sqrt{2}}={30\sqrt{2}\over3\sqrt{2}}\]denominator no longer matters:\[x\sqrt{2}+15=30\sqrt{2}\]subtract 15:\[x\sqrt{2}=30\sqrt{2}-15\]\[x=\underline{~~~~~~~~~~~~~~~~~~~~}?\]
hint:divide both sides by \(\sqrt{2}\)

Answer 16

30-15 square of 2 over 2

Answer 17

final answer ?