Question

12x^3+13x-22x-14/3x+4 using long division state the quotient and remainder. My answer is the quotient 4x^2-x-6 and the remainder is 10. Is math correct? Please and Thank you.

Answer 1

i think you meant that to be a \(+13x^2\) :)
\[\large{{12x^3+13x^2-22x-14}\over{3x+4}}~=~~4x^2-x-6,~~remainder=10~\checkmark \]

Answer 2

yes that's correct.

Answer 3

what class are you doing this for? :)

Answer 4

college algebra

Answer 5

that class shouldn't be a college credit, its too easy, lol.
but good job! :D

Answer 6

lol

Answer 7

is my math correct @yummydum?

Answer 8

that's why i put a check mark at the end, yes :)

Answer 9

and gave you a medal :P

Answer 10

and told you Good Job, lol.

Answer 11

Thank you I didn't see the check mark. sorry.
I have a few more questions; do you have any more time?

Answer 12

ive got a little bit, go ahead :)

Answer 13

Thank you ^_^. X^4-7x^3+4x^2-42x-12/x^2-7x-2

Answer 14

long division

Answer 15

please

Answer 16

\(x^2+6\) :)

Answer 17

no remainder right? ^_^

Answer 18

nope

Answer 19

thank u. 3x^5-4x^3-2x+7/x^2-2x

Answer 20

please

Answer 21

i think its \(3x^3+6x^2+8x+16\) not sure about the remainder

Answer 22

I got 30x+7 for the remainder.

Answer 23

yea i think so :)

Answer 24

thank u. x^2-4x-6/x+3 please.

Answer 25

x-7 with remainder 15

Answer 26

thank you. ^_^ the last one. 2x^5+3x^4-7x+8/x-1

Answer 27

\(2x^4+5x^3+5x^2+5x-2\) with remainder \(6\)

Answer 28

Thank you so much. I'm sorry I have one more. Is that okay? X^4-81/x+3. Please. ^_^