The perimeter of a rectangular concrete slab is 114 feet and the area is 702 square feet. How do I write a quadratic equation to solve this?
Draw pictures, they will help you in pretty much every math problem you come across. |dw:1364441492288:dw| Now you can plug in one equation for the other to get an expression that tells you what one side is.
Ok, how would I start to solve for w though?
So if you want W then you can just use your area formula and divide both sides by L to get: A/W=L Then plug that into your perimeter formula: P=2(A/W)+2W Now you have enough information to solve for W. =)
I'm confused
What in particular is confusing, if you can narrow it down?
I don't really understand how to find l or w. I know the equations should be 2l+2w=114 and lw=702.
Ok, well you have two equations and two variables, so you can plug one equation into the other. So when you see: LW=702 you can divide both sides by W to get: L=702/W With me so far? Now you have 2L+2W=114, and you have that other equation L=702/W so you can replace L with 702/W in the perimeter formula like this: 2L+2W=114 2(702/W)+2W=114 Does that make sense? Now you can see that you have 1404/W+2W=114 and you can rearrange that to solve for W.
Ok, so far I understand that.
Cool, now you just need to solve the quadratic formula after rearranging what you just got into something that looks like: ax^2+bx+c=0
So first, you would subtract 114 fro both sides? 1404/w+2w-114=114=114.
Yep except it all =0 now, not 114
1404/2+2w-114=0 Now you can multiply both sides by w and divide both sides by 2, try that out and show me what you get. It should make it look better. =D
1404/w+2w-114=0 whoops that's what I meant to write.
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