The probability that a dessert sold at a certain cafe contains chocolate is 73%. The probability that a dessert containing chocolate also contains nuts is 25%. Find the probability that a dessert chosen at random contains nuts given that it contains chocolate. Round to the nearest tenth of a percent.
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OpenStudy (anonymous):
@Luis_Rivera
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
Is my aswer 48 ?
OpenStudy (anonymous):
Whoops wrong question. This is the one i meant to post !
OpenStudy (anonymous):
An airline has 81% of its flights depart on schedule. It has 69% of its flights depart and arrive on schedule. Find the probability that a flight that departs on schedule also arrives on schedule.
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I posted the wrong question . Its above of what you said ^ ?
jimthompson5910 (jim_thompson5910):
one sec
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
P(Arrive On Schedule|Depart On Schedule) = P(Depart and Arrive On Schedule)/P(Depart On Schedule)
P(Arrive On Schedule|Depart On Schedule) = 0.69/0.81
P(Arrive On Schedule|Depart On Schedule) = 0.85185185185186
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OpenStudy (anonymous):
Thank you
OpenStudy (anonymous):
Find the values of the 30th and 90th percentiles of the data.
18, 9, 7, 5, 11, 7, 17, 20, 19, 2, 17, 12, 5, 1, 13, 12, 11, 15, 16, 20
OpenStudy (anonymous):
I got 30th percentile = 9
90th percentile = 20 but that answer isnt on my answer choice so what could it be ?
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
You there ?
jimthompson5910 (jim_thompson5910):
what do you get when you sort the data
OpenStudy (anonymous):
What do you mean ?
jimthompson5910 (jim_thompson5910):
when you arrange the list from smallest number to largest number, what do you get?
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OpenStudy (anonymous):
Huh ? I just posted the question. After doing the problem i got I got 30th percentile = 9
90th percentile = 20
But that answer isnt on my answer problem. So i posted you the answer choice to see what one is really my answer,
jimthompson5910 (jim_thompson5910):
example
the list 3, 1, 2 is not in order
but sorting them gives you 1, 2, 3
OpenStudy (anonymous):
exactly
jimthompson5910 (jim_thompson5910):
so sort the given list in your problem to get _____
OpenStudy (anonymous):
After i sort them then whats my answer ?
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jimthompson5910 (jim_thompson5910):
I'll show you how to find it once you've sorted it
OpenStudy (anonymous):
I have the correct answer just that correct answer isn't on my answer choice.
OpenStudy (anonymous):
is my answer 30th percentile = 9
90th percentile = 19
or
30th percentile = 7
90th percentile = 20
jimthompson5910 (jim_thompson5910):
the sorted list is
1, 2, 5, 5, 7, 7, 9, 11, 11, 12, 12, 13, 15, 16, 17, 17, 18, 19, 20, 20
jimthompson5910 (jim_thompson5910):
there are 20 values in this list
so the 30th percentile is at location number 0.3*20 = 6
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jimthompson5910 (jim_thompson5910):
So the the 30th percentile is at location number 6
So the differences are
-0.25, 0, 0.4, -0.35, -0.6, -0.1, 0.9
OpenStudy (anonymous):
is that it for my problem or answer ?
jimthompson5910 (jim_thompson5910):
Square each difference to get
(-0.25)^2 = 0.0625
(0)^2 = 0
(0.4)^2 = 0.16
(-0.35)^2 = 0.1225
(-0.6)^2 = 0.36
(-0.1)^2 = 0.01
(0.9)^2 = 0.81
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jimthompson5910 (jim_thompson5910):
So the list of squares are
0.0625, 0, 0.16, 0.1225, 0.36, 0.01, 0.81
jimthompson5910 (jim_thompson5910):
Add them up to get
0.0625+0+0.16+0.1225+0.36+0.01+0.81 = 1.525
Divide by 6 to get 1.525/6 = 0.25416666666667
and finally take the square root of that to get sqrt(0.25416666666667) = 0.5041494487418
OpenStudy (anonymous):
Is that it ? for my problem ?
jimthompson5910 (jim_thompson5910):
yeah I'm showing you how to find the variance and standard deviation
OpenStudy (anonymous):
whats my varicance
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jimthompson5910 (jim_thompson5910):
that would be 0.25416666666667 and I showed how you find it above
OpenStudy (anonymous):
Identify the type of sampling method used.
A trucking company places their office phone number on the back of all of their vehicles to receive comments on how well their employees are driving.
OpenStudy (anonymous):
i have 4 more thank you sooo much
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what are your choices for this one
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