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Mathematics 14 Online
OpenStudy (anonymous):

Let A be a square matrix such that A^3 = A. What can you say about the eigenvalues of A ?

OpenStudy (anonymous):

I am actually not really sure :/ .

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

@tkhunny @waterineyes

OpenStudy (anonymous):

My choices are: The eigenvalues of a matrix A can only be λ = 0, or λ = − 1. The eigenvalues of a matrix A can only be λ = 0, λ = 1, or λ = − 1. The eigenvalues of a matrix A can only be λ = 1, or λ = − 1. The eigenvalues of a matrix A can only be λ = 0. The eigenvalues of a matrix A can only be λ = 1. The eigenvalues of a matrix A can only be λ = 0, or λ = 1.

OpenStudy (anonymous):

I really thought it was the last one.

OpenStudy (anonymous):

@yummydum : No... I don't get it :/ .

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Eigendecomposition_(matrix) Eigendecomposition should give you a hint.

OpenStudy (anonymous):

We haven't even learned that in class :/ .

OpenStudy (anonymous):

:( .. well i dont know linear algebra i was just looking up stuff that could possibly help.. :\ hope you figure it out soon enough :)

OpenStudy (anonymous):

Basically it has to have eigen values such that \[ \lambda ^3=\lambda \]

OpenStudy (anonymous):

This is true for \(0, 1,-1\)

OpenStudy (anonymous):

Cube roots right... >.< . I forgot you can take the cube root of -1 >.< .

OpenStudy (anonymous):

At least that is my understanding, I'm rusty on this topic.

OpenStudy (anonymous):

It is correct :D . Thanks! I have to remember that cube roots are valid for negative numbers >.< .

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