Let A be a square matrix such that A^3 = A. What can you say about the eigenvalues of A ?
I am actually not really sure :/ .
@wio
@tkhunny @waterineyes
My choices are: The eigenvalues of a matrix A can only be λ = 0, or λ = − 1. The eigenvalues of a matrix A can only be λ = 0, λ = 1, or λ = − 1. The eigenvalues of a matrix A can only be λ = 1, or λ = − 1. The eigenvalues of a matrix A can only be λ = 0. The eigenvalues of a matrix A can only be λ = 1. The eigenvalues of a matrix A can only be λ = 0, or λ = 1.
I really thought it was the last one.
http://www.cliffsnotes.com/study_guide/Determining-the-Eigenvalues-of-a-Matrix.topicArticleId-20807,articleId-20803.html scroll down, i think it should be helpful ;)
@yummydum : No... I don't get it :/ .
http://en.wikipedia.org/wiki/Eigendecomposition_(matrix) Eigendecomposition should give you a hint.
We haven't even learned that in class :/ .
:( .. well i dont know linear algebra i was just looking up stuff that could possibly help.. :\ hope you figure it out soon enough :)
Basically it has to have eigen values such that \[ \lambda ^3=\lambda \]
This is true for \(0, 1,-1\)
Cube roots right... >.< . I forgot you can take the cube root of -1 >.< .
At least that is my understanding, I'm rusty on this topic.
It is correct :D . Thanks! I have to remember that cube roots are valid for negative numbers >.< .
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