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Mathematics 13 Online
OpenStudy (anonymous):

Integral

OpenStudy (anonymous):

How can I prove that mathematically!

hartnn (hartnn):

for perpendicular vectors, their dot product =0 you can prove this mathematically by the definition of dot product, a dot b = |a||b|cos theta theta = angle between them = 90

OpenStudy (anonymous):

and so the integral becomes, \[\int\limits_{a}^{b} 0\]

OpenStudy (anonymous):

which will give me a constant not zero, right?

OpenStudy (anonymous):

SO: \[\int\limits_{a}^{b} Vz . dz \] = \[\int\limits_{a}^{b} Vzdz costheta \]

OpenStudy (anonymous):

where cos theta= 0, and integral gives me a constant

hartnn (hartnn):

indefinite integral of 0 gives you 0.

hartnn (hartnn):

**definite

hartnn (hartnn):

\(\int 0 dx = +c \\ \int_a^b0dx=0\)

OpenStudy (anonymous):

ok then that makes sense, thank you =D actually thank you very much ;)

hartnn (hartnn):

welcome ^_^

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