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Mathematics 8 Online
OpenStudy (anonymous):

find the solution of the differential equation dy/dx=y^2+1 that satisfies the initial condition y(1)=0

hartnn (hartnn):

That is easily variable separable, are you having trouble integrating, 1/(y^2+1) dy ?

OpenStudy (abb0t):

Do the same thing as I explained in the previous problem. Separate them by term. Then integrate both sides.

OpenStudy (anonymous):

i understand the answer the answer of the differential equation i just don't understand the initial condition part.

OpenStudy (abb0t):

The initial conditions simply means x=1 and y=0

hartnn (hartnn):

you would have got +c after integration, right ? plug in x=1, y=0 to get the value of c

OpenStudy (abb0t):

What you're doing is basically finding a value for "C" which is you're constant.

OpenStudy (anonymous):

oohh, now i get it.

OpenStudy (anonymous):

now who wants a medal?

OpenStudy (abb0t):

Once you find a value for "C" plug in that value back into your solution. That will be now your explicit solution.

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