What is the specific heat of a substance if 17.0 grams of the substance require 0.52 kilojoules of heat to change the temperature by 3.6 degrees Celsius? (Points : 3) 8.5 x 10-3 J/g·°C 8.5 x 100 J/g·°C 8.5 x 102 J/g·°C 1.2 x 10−1 J/g·°C
Delta Q =M S delta T S= Delta Q /M Delta T put the values of Delata Q , Delta T and Delta Q and find the S
I am not sure that was English lol
then What langauage i should tellLOL:)
I just not sure where the Deltas come into play, chemistry is so not my cup of tea
delta symbol is triangle they use Delta T is nothing but only one parameter
S= 0.52 /17*3.6 can you do caluclate now
I got 0.11011765
0.52/61.2 u should get =0.0849 u get
0.00849
its unit is KJ/g °C
yes, my problem is converting that to one of the equations that the teacher gave as choices.
it becomes 8.5 J/g °C but which not in ur choice LOL some thing mistake is their in ur options
hmm that is what we have been thinking that the teacher is not being correct... I think the second best option would be 8.5 x 10^0 g c?
yaaa is it 10^) LOL u have not mentioned here
yeah I should have noticed that mistake sorry.. so ready for the next one?? :+D
LOL:) OK
What is the specific heat of a substance if 12.6 grams of the substance requires 0.119 kilojoules of heat to increase the temperature by 5.9 degrees Celsius? (Points : 3) 1.6 x 100 J/g·°C 1.6 x 10−3 J/g·°C 1.6 x 103 J/g·°C 6.2 x 10−1 J/g·°C
LOL u ask in question box so all can view it
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