Question

Please help!! What are the restrictions for x(x-1)(x-2)? I already solved the problem and this is the denominator...I'm not sure how to find the restrictions.

Answer 1

if this is denominator, it can't be 0. So find it's roots : x(x-1)(x-2)=0
It will be at x=0, x=1, and x=2

Answer 2

Oh ok. So do I set the whole thing equal to 0 or x(x-1)=0 or x(x-2)=0? The restircitons are 0, 1, and 2?

Answer 3

@myko ??? Wait so what are the restrictions??

Answer 4

The hall thing. The restrictions are the roots.

Answer 5

Oh ok! So it's 0, 1, and 2?

Answer 6

as you know, the fraction can't have 0 denominator, because then it's not defined. Sincé x(x-1)(x-2) is the denominator, any value of x, that makes it 0 is not alowed. For example, when x=2, we eill have 2(2-1)(2-2)=2(1)(0)=0. So x=2 is not alowed. It is a restriction. Same for x=0, and x=1

Answer 7

ok?

Answer 8

THANK YOU!!

Answer 9

yw