Please Help with Practice question!!!
An electrically charged particle accelerates uniformly from rest to speed v while traveling a distance x.
a) Show the acceleration of the particle is a= v^2/2x.
b) If the particle starts from rest and reaches a speed of 1.8 x 10^7 m/s over a distance of 0.10m, show that its acceleration is 1.6 x 10^15 m/s^2.

Question

Please Help with Practice question!!!
An electrically charged particle accelerates uniformly from rest to speed v while traveling a distance x.
a) Show the acceleration of the particle is a= v^2/2x.
b) If the particle starts from rest and reaches a speed of 1.8 x 10^7 m/s over a distance of 0.10m, show that its acceleration is 1.6 x 10^15 m/s^2.

anonymous · Answer

I know for B i just plug in the numbers...

shivaniits · Answer

you know $$v ^{2}-u ^{2}=2as$$
and here s=x and u=0 since it started from rest so we have:-
$$v ^{2}-0=2ax$$

$$a=v ^{2}/2x$$

shivaniits · Answer

now for second part just put the values for the equation..
hope this helps..!!

anonymous · Answer

so the equation for part A is ...

anonymous · Answer

v^2-0=2ax?

shivaniits · Answer

yup that'w what you get after putting in the values x=s and u=0 in more general eqn $$v ^{2}-u ^{2}=2as$$

anonymous · Answer

ok, then for B it comes out like ...

anonymous · Answer

[1.8 x 10^7]^2/ {2*0.1)  ?

shivaniits · Answer

yes..

shivaniits · Answer

hope this sorted you out..!!

anonymous · Answer

so it equals ...

anonymous · Answer

1.62e + 15 m/s^2  ?

anonymous · Answer

thats what comes up on a calculator.....

shivaniits · Answer

oh..the answer is  $$16.2 \times 10^{14}$$

anonymous · Answer

ok.......

anonymous · Answer

hmm wonder why  mine is so off...

shivaniits · Answer

everything alright..!!