How to solve this?
\[\LARGE (0.2)^{\log_\sqrt{5}} 0.2\]
I am not getting your question..
why?
What is in the power of 0.2??
log base root 5 (0.2)
\[\LARGE (0.2)^{{\log_\sqrt{5}} 0.2}\]
@waterineyes fixed
Yeah, I was not getting the last 0.2 part, now it is okay..
so now??
Wait..
Are your real name is Shivam, if I am not wrong then??
:O yes
Okay, I don't know how to proceed in an efficient way but I have two formulas with me, so let us try by using them: \[\log_{a^{n}}N = \frac{1}{n} \cdot \log_a N\]
Shouldn't we consider changing bases?
If you know how to change the base then it is enough to solve it I think.. I don't know how to do that, can you please write the formula here??
@shubhamsrg who else?
@shubhamsrg
Maybe @Yahoo!
But how is changing the base gonna help anyway :/
Thank you thank you.
There is one more formula if we can reduce this to that, then we can solve this: \[a^{\log_a{N}} = N\]
We have 0.2 below and if we can bring 0.2 in base, then we can easily solve this, but my mind is not working here that how can we do this.. @amistre64 , here moderator help required..
change of base is:\[log_{base}(arg)=\frac{ln(arg)}{ln(base)}\] of course this works for any change and not just ln
Still this gives root 5 which is wrong
\[\LARGE (0.2)^{{\log_\sqrt{5}} (0.2)}=N\] \[\LARGE {\log_\sqrt{5}} (0.2)=log_{0.2}(N)\] \[\LARGE \frac{ln(0.2)}{\frac12ln(5)}=\frac{ln(N)}{ln(0.2)}\] \[\LARGE 2\frac{(ln(0.2))^2}{ln(5)}=ln(N)\] \[\LARGE exp(2\frac{(ln(0.2))^2}{ln(5)})=N \]
the answer is 2.
http://www.wolframalpha.com/input/?i=.2%5E%28log%28.2%29%2Flog%28sqrt%285%29%29%29 no, its should still be 25
or, youve asked the wrong question ...
okay,what if we had 0.5 instead of 0.2 ?
in the power
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