Multiply
\[\frac{ 5x + 10 }{ x+2 } , \frac{ 2x }{ 4x-10 }\]
Can you reduce this fraction?? \[\frac{2x}{4x - 10}\] Factor out 2 in denominator first and cancel whatever is being cancelled..
\[\frac{ 1x }{ 2x-5 }\] ?
Yeah right.. Similarly do it for first fraction: \[\frac{ 5x + 10 }{ x+2 }\] Factor out 5 and cancel..
\[\frac{ 1x + 2 }{ x+2 }\] ... I think I messed up because well idk but it doesn't look right
See it goes like this: \[\frac{ 5x + 10 }{ x+2 } \implies \frac{5(x + 2)}{(x + 2)} \implies \frac{5 \cancel{(x + 2)}}{\cancel{(x + 2)}} \implies 5\] Getting??
So now multiply the two fractions: \[\implies 5 \times \frac{x}{2x - 5} = ??\]
Am I supposed to factor that too or do I distribute 4 into x, 2x, and -5 ?
or do I make 5 into 1/5
Distribute 4??
I meant 5 lol sorry
See if there is only 5 in the numerator then it means there is 1 in denominator : \[5 \implies \frac{5}{1}\]
then it would be \[\frac{ 5x }{ 2x-5 } ?\]
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