A charge of +5μC is located somewhere inside a closed hollow cube with sides 30 cm long. What is the electric flux through the closed surface of this box?
5.6×10**5 x Nm**2/C

Can somebody tell me, why?

Question

A charge of +5μC is located somewhere inside a closed hollow cube with sides 30 cm long. What is the electric flux through the closed surface of this box? 
5.6×10**5 x Nm**2/C

Can somebody tell me, why?

anonymous · Answer

apply Gauss' Law
it states that
Flux = total charge enclosed / total surface area

anonymous · Answer

correction, that gives you the Electric field.
flux is jsut the total field around the conductor
so, 
$$\Phi={Q\over\epsilon}$$
where $\epsilon$ is the permittivitty of the medium

anonymous · Answer

also u gota use columbs law

anonymous · Answer

@luvvictor no need. just plug in Q and value for epsilon, and you'd get the answer