Question

What are the solutions of the equation?

z² – 6z – 27 = 0

Answer 1

(3,9) (3,-9) (-3,9) (-3,-9)

Answer 2

First find the delta: b^2-4ac

then for finding the answer use this....\[(-b \pm \sqrt{\Delta})\div2a\]

Answer 3

huh?

Answer 4

let me show the steps...

Answer 5

yes please!

Answer 6

You can write this equation like this: \[az ^{2}+bz+c\]
ok?

Answer 7

yeah

Answer 8

For finding answers of this equation you will need Delta...
\[\Delta=b ^{2}-4ac\]
if delta>0 then you have two answers...

if delta=0 then you have one answer...

if delta <0 then you don't have answer for the equation...

Answer 9

For finding answer you should use this:

\[(-b \pm \sqrt{\Delta})\div2a\]

Answer 10

i have no clue how. that is gibberish to me

Answer 11

in this equation a=1 and b= -6 and c= -27
ok?

Answer 12

yeah i got that part

Answer 13

Delta = \[(-6)^{2}-4(1)(-27)=144\]
ok?

Answer 14

nope lost me

Answer 15

Δ=\[b ^{2}-4ac\]

here b=-6 and a=1 and c=-27 ....just put the nimbers in the delta equation...ok?

Answer 16

ok so what do i do with the 144?

Answer 17

delta is 144 and we need it to find the answers...

Delta > 0 then we should have two answers...

Answers = \[(-b+\sqrt{\Delta})\div2a\] and \[(-b-\sqrt{\Delta})\div2a\]

Just put numbers and get the answers...
answers are....???

Answer 18

-3 and 9
got them?

Answer 19

no clue how you got them but thanks!

Answer 20

Look i will show you...

\[(-(-6)+\sqrt{144})\div2(1)=9\]

\[(-(-6) -\sqrt{144})\div2(1)\]=-3

just remember b=(-6) , a=1 , c=-27 , delta=144

Answer 21

Need more explain...?