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OpenStudy (anonymous):
OpenStudy (anonymous):
anything to the power of 0 is 1
OpenStudy (anonymous):
that's a powerful hint right there
OpenStudy (anonymous):
and anything to power of -1 flips
OpenStudy (anonymous):
Is B the correct answer?
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OpenStudy (anonymous):
1. since the first paranthesis is to the power of "0", its value is "1" aand can be ignored.
2. check the power of "x" in the two paranthesis
\(\left(1\over x^5\right)^{-1}=x^5\)
so, x^5 should be on the numerator. so, we narrow down our options to B and D
3. notice that they have the same power for "z". so, lets check for the powers of "y" in both the paranthesis
OpenStudy (anonymous):
@electrokid would B be correct?
OpenStudy (anonymous):
did you sum up the powers of "y"?
OpenStudy (anonymous):
It is D!!! because the sums of y are 3, right?
OpenStudy (anonymous):
@electrokid
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OpenStudy (anonymous):
either this or that!!! bad procedure!
"b" is correct.