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Mathematics 57 Online
OpenStudy (anonymous):

PLEASE HELP!

OpenStudy (anonymous):

OpenStudy (anonymous):

anything to the power of 0 is 1

OpenStudy (anonymous):

that's a powerful hint right there

OpenStudy (anonymous):

and anything to power of -1 flips

OpenStudy (anonymous):

Is B the correct answer?

OpenStudy (anonymous):

1. since the first paranthesis is to the power of "0", its value is "1" aand can be ignored. 2. check the power of "x" in the two paranthesis \(\left(1\over x^5\right)^{-1}=x^5\) so, x^5 should be on the numerator. so, we narrow down our options to B and D 3. notice that they have the same power for "z". so, lets check for the powers of "y" in both the paranthesis

OpenStudy (anonymous):

@electrokid would B be correct?

OpenStudy (anonymous):

did you sum up the powers of "y"?

OpenStudy (anonymous):

It is D!!! because the sums of y are 3, right?

OpenStudy (anonymous):

@electrokid

OpenStudy (anonymous):

either this or that!!! bad procedure! "b" is correct.

OpenStudy (anonymous):

Oh I am sorry :( thanks anyway!!:(

OpenStudy (anonymous):

all you had to do was "ADD"

OpenStudy (anonymous):

powers of y: -1+(-1)(-2)=-1+2=1

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