PLEASE HELP!
anything to the power of 0 is 1
that's a powerful hint right there
and anything to power of -1 flips
Is B the correct answer?
1. since the first paranthesis is to the power of "0", its value is "1" aand can be ignored. 2. check the power of "x" in the two paranthesis \(\left(1\over x^5\right)^{-1}=x^5\) so, x^5 should be on the numerator. so, we narrow down our options to B and D 3. notice that they have the same power for "z". so, lets check for the powers of "y" in both the paranthesis
@electrokid would B be correct?
did you sum up the powers of "y"?
It is D!!! because the sums of y are 3, right?
@electrokid
either this or that!!! bad procedure! "b" is correct.
Oh I am sorry :( thanks anyway!!:(
all you had to do was "ADD"
powers of y: -1+(-1)(-2)=-1+2=1
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