Question

@jim_thompson5910 Graph the circle with center at (-4, -3), which also passes through the point (0, 3). Label the center and at least four points on the
circle. Write the equation of the circle.

Answer 1

@jim_thompson5910

Answer 2

@jim_thompson5910

Answer 3

@jim_thompson5910

Answer 4

You first need to find the distance from (-4,-3) to (0,3)

Answer 5

so you would use the distance formula again

Answer 6

can you set it please :)

Answer 7

d = sqrt((x2-x1)^2+(y2-y1)^2)

Answer 8

x1=-4
y1=-3

x2=0
y2=3

Answer 9

that gives you


d = sqrt((x2-x1)^2+(y2-y1)^2)


d = sqrt((0-(-4))^2+(3-(-3))^2)


d = sqrt((0+4)^2+(3+3)^2)


d = sqrt((4)^2+(6)^2)


d = ???

Answer 10

16+36

Answer 11

keep going

Answer 12

52

Answer 13

now what

Answer 14

so the distance is \[\Large d = \sqrt{52}\]

Answer 15

The radius is \[\Large r = \sqrt{52}\]

So \[\Large r^2 = 52\]

Answer 16

@jim_thompson5910 so the radius i have to go 52 directions?

Answer 17

\[\Large \sqrt{52} \approx 7.21110255\]

Answer 18

So you roughly have to go 7.2 units in each direction starting at the center

Answer 19

can you show me how you go 7.2 units?

Answer 20

you'll have to go 7 units, then a bit more (not 8 units though)

So it's between 7 and 8, but much closer to 7 (than 8)

Answer 21

ok cool wheres my center?

Answer 22

-4,3?

Answer 23

(-4, -3)

Answer 24

k

Answer 25

isnt it positive 3?

Answer 26

oh nvm

Answer 27

no it' negative

Answer 28

it's*